2sin^2x-6cosx+1=0

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Solution for 2sin^2x-6cosx+1=0 equation: 


Simplifying
2sin2x + -6cosx + 1 = 0

Reorder the terms:
1 + -6cosx + 2in2sx = 0

Solving
1 + -6cosx + 2in2sx = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -6cosx + -1 + 2in2sx = 0 + -1

Reorder the terms:
1 + -1 + -6cosx + 2in2sx = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -6cosx + 2in2sx = 0 + -1
-6cosx + 2in2sx = 0 + -1

Combine like terms: 0 + -1 = -1
-6cosx + 2in2sx = -1

Add '-2in2sx' to each side of the equation.
-6cosx + 2in2sx + -2in2sx = -1 + -2in2sx

Combine like terms: 2in2sx + -2in2sx = 0
-6cosx + 0 = -1 + -2in2sx
-6cosx = -1 + -2in2sx

Divide each side by '-6osx'.
c = 0.1666666667o-1s-1x-1 + 0.3333333333in2o-1

Simplifying
c = 0.1666666667o-1s-1x-1 + 0.3333333333in2o-1

Reorder the terms:
c = 0.3333333333in2o-1 + 0.1666666667o-1s-1x-1

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